garázs Bizottság Bonyolult a 2 b 2 c 2 ab bc ac következtetés Kápráztató egyedi
Using properties of determinant, prove that (a + b + c) (a2 + b2 + c2)
i) If a^(2)+b^(2)+c^(2)=20 " and" a+b+c=0, " find " ab+bc+ac. (ii) If a^(2)+ b^(2)+c^(2)=250 " and" ab+bc+ca=3, " find" a+b+c. (iii) If a+b+c=11 and ab+ bc+ca=25, then find the value of a^(3)+b^(3)+c^(3)-3 abc.
Extract the square root of (a^2 + ab + bc + ca)(bc + ca + ab + b^2)(bc + ca + ab + c^2)
ab + bc + ca does not exceed aa + bb + cc
If a^2+b^2+c^2+ab+bc+ca<=0 AA a, b, c in R then find the value of the determinant |[(a+b+2)^2, a^2+b^2, 1] , [1, (b+c+2)^2, b^2+c^2] , [c^2+a^2, 1, (c+a+2)^2]| : (A) abc(a^2 + b^2 +c^2) (
If a^2 + b^2 + c^2 = 20 and a + b + c = 0 , find ab + bc + ca .
If a^2 + b^2 + c^2 - ab - bc - ca = 0 , prove that a = b = c .